Grade 11 · Chemistry · Lesson 6

Rate of Reaction

Define reaction rate, explain factors that affect it using collision theory, interpret rate graphs, and understand the role of catalysts.

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What Is Reaction Rate?

Reaction rate is defined as the change in concentration of a reactant (or product) per unit time. As a reaction proceeds, reactants are consumed and products are formed.

Rate = Δ[concentration] / Δt    (units: mol·L−1·s−1)

Rate can also be measured experimentally by:

There are two types of rate:

Why does rate decrease over time? As reactants are consumed, there are fewer reactant particles per unit volume. This reduces the frequency of collisions, which reduces the rate. On a concentration-time graph, the curve becomes less steep as time passes.

Collision Theory

Collision theory explains why and how reactions occur at the particle level. For a reaction to occur, particles must:

A collision that meets both energy and orientation requirements is called an effective collision. Only effective collisions lead to a reaction. The rate of reaction is proportional to the frequency of effective collisions.

Rate ∝ frequency of effective collisions = frequency of collisions × fraction with E ≥ Ea × fraction with correct orientation

Factors Affecting Reaction Rate

1. Concentration (solutions)

Increasing the concentration of a dissolved reactant increases the number of particles per unit volume. This leads to more frequent collisions per second, and therefore more effective collisions per second, increasing the rate.

2. Pressure (gases)

For reactions involving gases, increasing pressure compresses the gas into a smaller volume. This increases the number of gas particles per unit volume — the same effect as increasing concentration. Higher pressure → more frequent collisions → higher rate.

3. Surface Area (solids)

Reactions between a solid and a liquid (or gas) can only occur at the surface of the solid. Breaking a solid into smaller pieces (e.g., powder vs. lumps) increases the total surface area exposed to the reactant, so more particles are available to collide. This increases the rate.

Explosion risk: Fine dust (coal dust, flour dust) has enormous surface area and can react extremely rapidly with oxygen — leading to explosions. This is why dust in mines and mills is a serious safety hazard.

4. Temperature

Increasing temperature has two effects that both increase the reaction rate:

The second effect (more particles exceeding Ea) is the dominant one. As a rough rule of thumb, reaction rate approximately doubles for every 10°C rise in temperature for many reactions.

5. Catalysts

A catalyst is a substance that increases the rate of a reaction without being consumed in the process. It provides an alternative reaction pathway with a lower activation energy.

Maxwell-Boltzmann Distribution

The Maxwell-Boltzmann distribution is a graph showing the distribution of kinetic energies among particles in a gas at a given temperature. Key features:

Effect of temperature increase:

The Ea line stays fixed when temperature changes. The catalyst lowers the Ea line (shifts it left), increasing the shaded area without changing the curve shape.

Rate-Time and Concentration-Time Graphs

Graph typeReactantProductKey interpretation
Concentration vs timeDecreasing concave curveIncreasing concave curve (flattens)Gradient at any point = instantaneous rate
Rate vs timeStarts high, decreases to near zeroSame shapeRate is always positive; decreases as reactants consumed
Volume of gas vs timeN/AIncreasing curve, levels offInitial gradient = initial rate; final volume = when reactant exhausted
⭐ IEB Extension — Rate Law and Reaction Order

The rate law (or rate equation) expresses the rate as a function of reactant concentrations:

rate = k[A]m[B]n
  • k = rate constant (depends on temperature; determined experimentally)
  • m, n = orders of reaction with respect to A and B (must be determined from experiment, not from stoichiometry)
  • Overall order = m + n

To determine orders from experimental data: compare experiments where one concentration is changed while the other is kept constant. If doubling [A] doubles the rate: first order (m=1). If doubling [A] quadruples the rate: second order (m=2).

⭐ IEB Extension — Half-Life and Arrhenius Equation

For a first-order reaction, the half-life t½ is constant and independent of initial concentration:

t½ = 0.693 / k

The Arrhenius equation relates the rate constant k to temperature T (in Kelvin) and activation energy Ea:

k = Ae(−Ea/RT)

Where A is the pre-exponential (frequency) factor and R = 8.314 J·mol−1·K−1. As T increases, k increases — confirming that rate increases with temperature. A catalyst lowers Ea, which increases k at the same temperature.

Gas Volume vs Time — Marble Chips + HCl

Reaction Conditions
Medium
25°C
Chips
Rate Readouts
Initial Rate
--cm³/s
Max Volume
--cm³
Rate Factor
1.0×
Condition
--
0/6
Quiz complete! Review the explanations to strengthen your understanding.
IEB Extension Questions
Answer all questions in your notebook. Use collision theory where required. Sketch graphs neatly with labelled axes, including units.
Question 1 — Surface Area and Collision Theory
A learner reacts equal masses of marble (CaCO₃) with excess HCl under two conditions: (A) a single large piece of marble and (B) marble powder.

(a) Predict which produces gas faster. Explain using collision theory (mention particle exposure and collision frequency).
(b) Will the total volume of CO₂ gas produced be the same or different for A and B? Explain.
(c) Sketch volume-of-gas vs time curves for both experiments on the same axes. Label the curves A and B. Indicate which has a steeper initial gradient and which reaches the final volume first.
(6 marks)
Question 2 — Concentration-Time Graph Interpretation
The concentration-time graph for the decomposition of N₂O₅ is a decreasing curve that starts steep and gradually flattens.

(a) Explain why the curve is steep at the beginning and becomes less steep over time.
(b) How would you determine the instantaneous rate at t = 30 s from the graph? Describe the method clearly.
(c) The average rate between t = 0 and t = 60 s is 0.015 mol·L−1·s−1. If [N₂O₅] at t = 0 is 1.80 mol·L−1, what is [N₂O₅] at t = 60 s?
(5 marks)
Question 3 — Comparing Two Conditions
The reaction Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g) is carried out at 20°C with 1.0 mol·L−1 HCl. A second experiment uses the same mass of Mg at 50°C with 2.0 mol·L−1 HCl.

(a) State two differences in conditions between the experiments.
(b) Predict which experiment will have the higher initial rate. Justify your answer in terms of collision theory (address each factor separately).
(c) If a catalyst were added to the first experiment, would the final amount of H₂ gas produced change? Explain.
(5 marks)
Question 4 — Calculating Average Rate from Data
The table below shows the volume of CO₂ gas collected at different times during the reaction of excess HCl with marble chips:

Time (s)01020406080
Volume CO₂ (cm³)01831485557
(a) Calculate the average rate of gas production between t = 0 and t = 10 s (in cm³·s−1).
(b) Calculate the average rate between t = 40 s and t = 80 s.
(c) Explain why the rate is different in (a) and (b).
(d) What has happened to the reaction at t = 80 s? How can you tell from the data?
(5 marks)
Question 5 — Catalyst Explanation
The decomposition of hydrogen peroxide is normally very slow: 2H₂O₂(l) → 2H₂O(l) + O₂(g). In the presence of MnO₂(s), the reaction proceeds vigorously.

(a) Identify the type of catalyst (homogeneous or heterogeneous). Explain your answer.
(b) Using the concept of activation energy and the Maxwell-Boltzmann distribution, explain why MnO₂ increases the reaction rate.
(c) After the reaction is complete, MnO₂ is recovered unchanged. What does this tell you about the role of a catalyst?
(d) If the temperature were increased at the same time as adding the catalyst, would the rate increase be greater than if only the catalyst were added? Explain using two separate effects.
(6 marks)