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Grade 12 · Organic chemistry · Paper 2

IUPAC naming and isomers

Name and draw organic compounds from all nine homologous series, step by step, and identify chain, positional and functional isomers.

The nine homologous series

SeriesFunctional groupName ending / prefixExample
Alkanesonly C–C single bonds-anepropane
AlkenesC=C double bond-enebut-1-ene
AlkynesC≡C triple bond-ynepropyne
Haloalkanes–X (F, Cl, Br, I)fluoro-, chloro-, bromo-, iodo-2-chloropropane
Alcohols–OH (hydroxyl)-olethanol
Aldehydes–CHO (formyl, at the end of the chain)-alpropanal
KetonesC=O inside the chain (carbonyl)-onepropanone
Carboxylic acids–COOH (carboxyl)-oic acidethanoic acid
Esters–COO– between two chainsalkyl alkanoatemethyl ethanoate

Chain prefixes: meth (1), eth (2), prop (3), but (4), pent (5), hex (6), hept (7), oct (8).

Naming in five steps

  1. Find the longest continuous carbon chain that contains the functional group. This gives the stem.
  2. Number the chain from the end that gives the functional group the lowest number. (For alkanes and haloalkanes, give the substituents the lowest numbers.)
  3. Name the branches (methyl, ethyl) and halogens with their position numbers.
  4. List substituents in alphabetical order; use di-, tri-, tetra- for repeats (these prefixes are ignored when alphabetising).
  5. Punctuation: commas between numbers, hyphens between numbers and letters, no spaces (except in acids and esters).
✏️ Worked examples
1CH₃CH(CH₃)CH(CH₃)CH₃ — longest chain 4 C, methyl groups on C2 and C3: 2,3-dimethylbutane.
2CH₃CH=CHCH(CH₃)CH₃ — 5 C chain with the double bond; number from the left so C=C starts at C2; methyl on C4: 4-methylpent-2-ene.
3CH₃CHBrCH(CH₃)CH₃ — 4 C chain; Br on C2, methyl on C3; bromo before methyl alphabetically: 2-bromo-3-methylbutane.
4CH₃CH(CH₃)CH₂OH — 3 C chain containing the C bonded to OH; number from the OH end: 2-methylpropan-1-ol.

Naming esters

An ester forms when an alcohol reacts with a carboxylic acid (esterification, catalysed by concentrated H₂SO₄). The name has two words: the alkyl group from the alcohol first, then the alkanoate from the acid.

✏️ Worked example
1Propan-1-ol + ethanoic acid → propyl ethanoate + water.
2Reading a formula: in CH₃COOCH₂CH₃, the C=O carbon belongs to the acid part (2 C → ethanoate) and the chain on the single-bonded O comes from the alcohol (2 C → ethyl): ethyl ethanoate.

Structural isomers

Structural isomers are organic molecules with the same molecular formula but different structural formulae.

Common mark losses: choosing a chain that misses the functional group; numbering from the wrong end; forgetting hydrogen atoms on a structural formula; writing “2-methyl-butane” or “2,3 dimethylbutane”.
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Review the explanations above.
Answer in your exercise book, then open each memo to mark your work.
Question 1 · (2 marks)
Define structural isomers.
Show memo
Organic molecules with the same molecular formula ✓ but different structural formulae ✓.
Question 2 · (4 marks)
Write the IUPAC names of: (a) CH₃CH₂CH(CH₃)CH₂CH₃ (b) CH₃COCH₂CH₃ (c) CH₃CH₂CH₂COOH (d) HCOOCH₃
Show memo
(a) 3-methylpentane ✓ (b) butan-2-one (accept butanone) ✓ (c) butanoic acid ✓ (d) methyl methanoate ✓
Question 3 · (4 marks)
Draw the structural formula of 2-chloro-3-methylpentane and state the homologous series it belongs to.
Show memo
Five-carbon chain ✓; Cl on C2 ✓ and CH₃ on C3 ✓, all H atoms shown. Haloalkanes ✓.
Question 4 · (4 marks)
C₄H₈O₂ can be a carboxylic acid or an ester. (a) Name the type of isomerism. (b) Give the IUPAC name of one acid and one ester with this formula. (c) Name the alcohol and acid used to make your ester.
Show memo
(a) Functional (group) isomers ✓
(b) Butanoic acid (or 2-methylpropanoic acid) ✓; ethyl ethanoate (or methyl propanoate / propyl methanoate) ✓
(c) For ethyl ethanoate: ethanol and ethanoic acid ✓