Grade 12 · Chemistry · Lesson 1

Organic Chemistry — Structure & Naming

Identify and name organic compounds using IUPAC nomenclature, classify functional groups, and describe the physical properties of homologous series.

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What is Organic Chemistry?

Organic chemistry is the study of compounds containing carbon. Carbon is unique: it forms four covalent bonds, can bond to itself in chains or rings, and produces millions of different compounds. Almost all biological molecules — proteins, DNA, fats, sugars — are organic.

Key features of carbon: Tetravalent (4 bonds); forms C–C single bonds, C=C double bonds, C≡C triple bonds; bonds are covalent (not ionic); non-polar C–H bonds give organic compounds hydrophobic character unless a polar functional group is present.

Hydrocarbons

Hydrocarbons contain only carbon and hydrogen. They are classified by the type of C–C bonding:

SeriesGeneral FormulaBond typeExample
AlkanesCnH2n+2Single bonds only (saturated)CH4, C2H6, C3H8
AlkenesCnH2nAt least one C=C double bondC2H4, C3H6
AlkynesCnH2n−2At least one C≡C triple bondC2H2

IUPAC Naming Rules

IUPAC (International Union of Pure and Applied Chemistry) provides a systematic naming system:

but-2-ene → 4-carbon chain, double bond starting at C2
2-methylpropane → propane with a methyl group on C2
3-chlorobutan-1-ol → 4-carbon chain, Cl on C3, OH on C1

Functional Groups

Functional GroupStructureClassSuffix
Hydroxyl–OHAlcohols-ol
Carboxyl–COOHCarboxylic acids-oic acid
Amino–NH2Amines-amine
Ester linkage–COO–Esters-oate
Halogen–X (F, Cl, Br, I)Halogenoalkaneshalo- prefix
Carbonyl (aldehyde)–CHO (end)Aldehydes-al
Carbonyl (ketone)–C(=O)– (middle)Ketones-one

Structural Formulae

Isomers

Structural isomers have the same molecular formula but different structural arrangements:

Geometric isomers arise from restricted rotation around a C=C double bond. When both carbons of a double bond carry two different groups:

Condition for geometric isomerism: Each carbon of the C=C must bear two different substituents. If either carbon has two identical groups, no cis/trans isomers exist.

Physical Properties of Homologous Series

A homologous series is a family of compounds with the same functional group and general formula, differing by –CH2– units. Properties change gradually along the series:

FactorEffect on BPReason
Longer chainIncreasesMore surface area, stronger London forces
More branchingDecreasesMore compact shape, less surface contact
–OH groupGreatly increasesHydrogen bonding (strong intermolecular force)
–COOH groupEven higher increaseDimerisation via 2 H-bonds; also polar C=O

Worked Naming Examples

CH3CH2CH2CH3 → butane (4-carbon chain, no functional group, alkane suffix -ane)

CH3CH=CHCH3 → but-2-ene (4C chain, double bond at C2)

CH3CH(OH)CH3 → propan-2-ol (3C chain, OH on C2)

CH3COOH → ethanoic acid (2C chain, carboxyl group: suffix -oic acid)

CH3CH(CH3)CH2CH3 → 2-methylbutane (4C parent chain + methyl branch on C2)
⭐ IEB Extension — Stereoisomers & Optical Isomers

Beyond geometric isomers, molecules can exhibit optical isomerism. A carbon atom bonded to four different groups is called a chiral centre (or stereocentre). The two non-superimposable mirror-image structures are called enantiomers.

Enantiomers rotate plane-polarised light in opposite directions: the (+) or R enantiomer and the (−) or S enantiomer. The R/S designation uses the Cahn–Ingold–Prelog (CIP) priority rules:

  • Assign priorities 1–4 to the four substituents by atomic number (highest = 1).
  • View the molecule with the lowest priority group (4) pointing away from you.
  • If 1→2→3 is clockwise → R configuration; anticlockwise → S.

A racemic mixture (50:50 mixture of enantiomers) shows no net optical rotation. Enantiomers have identical physical properties except optical rotation, but can have very different biological activity (e.g. thalidomide, ibuprofen).

Molecule Builder — Draw Structural Formulae

Build Your Molecule
IUPAC Name & Formula
IUPAC Name
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Molecular Formula
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Series
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Quiz complete! Review the explanations to strengthen your understanding.
IEB Extension Questions
Answer all questions in your notebook. Show all reasoning clearly. For naming questions, identify the parent chain and functional group position step by step.
Question 1 — IUPAC Naming
Name the following compounds using IUPAC nomenclature. Show your reasoning (identify parent chain, functional group, locant):

(a) CH3CH2CH2OH
(b) CH3CHCH2CH3 with a Cl on the second carbon
(c) CH3CH2COOH
(d) CH3CH=CHCH2CH3

(8 marks — 2 per compound)
Question 2 — Functional Groups & Classification
For each compound below, (i) identify the functional group present, (ii) name the homologous series it belongs to, and (iii) draw the structural formula:

(a) hexan-1-ol    (b) propanoic acid    (c) 2-chloropropane    (d) pentan-3-one

(8 marks — 2 per compound)
Question 3 — Isomers
The molecular formula C4H8O can represent several different compounds.

(a) Draw TWO structural isomers that are aldehydes with this formula.
(b) Draw ONE structural isomer that is a ketone with this formula.
(c) For but-2-ene (C4H8), draw and label the cis and trans isomers. Explain why geometric isomers are possible for this compound.

(7 marks)
Question 4 — Physical Properties
Consider the following compounds: butane (C4H10), butan-1-ol (C4H9OH), and 2-methylpropan-1-ol (C4H9OH).

(a) Which compound has the highest boiling point? Explain fully using intermolecular forces.
(b) Which of the two C4 alcohols has the higher boiling point? Explain the effect of branching.
(c) Which of these three compounds is most soluble in water? Explain.

(6 marks)
Question 5 — Boiling Point Trend in a Homologous Series
The table shows the boiling points of the first five straight-chain primary alcohols:
AlcoholMethanolEthanolPropan-1-olButan-1-olPentan-1-ol
FormulaCH3OHC2H5OHC3H7OHC4H9OHC5H11OH
Boiling point (°C)657897118138
(a) Describe the trend in boiling point as chain length increases down this table.
(b) Calculate the increase in boiling point between each consecutive pair of alcohols. Is the increase per added −CH2− group exactly constant?
(c) Using the increase between butan-1-ol and pentan-1-ol, predict the boiling point of hexan-1-ol (the next member of the series).
(d) Every alcohol in this table can hydrogen-bond. Explain, in terms of intermolecular forces, why the boiling point still increases steadily down the series even though all five have the same STRONGEST type of intermolecular force.

(8 marks)