Grade 12 · Chemistry · Lesson 2

Organic Reactions

Write equations for addition, elimination, substitution, esterification, and hydrolysis reactions, and explain the conditions required for each.

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Addition Reactions (Alkenes only)

Addition reactions occur across the C=C double bond. The double bond breaks and atoms add to both carbons. Alkenes are unsaturated — they can accommodate additional atoms by converting C=C to C–C.

ReagentReaction typeConditionsProducts
H2HydrogenationNi/Pt catalyst, heatAlkane (saturated)
HX (HBr, HCl)HydrohalogenationRoom temp, no catalystHalogenoalkane
H2OHydrationH3PO4/H2SO4 catalyst, heatAlcohol
X2 (Br2, Cl2)HalogenationRoom temp (test: bromine water decolourises)Dihalogenoalkane
Markovnikov’s Rule: When HX adds to an unsymmetrical alkene, the H atom adds to the carbon with more hydrogen atoms already attached (the less substituted carbon), and X adds to the carbon with fewer H atoms (the more substituted carbon). “The rich get richer.”
CH2=CH2 + Br2 → CH2BrCH2Br    (1,2-dibromoethane)
CH2=CHCH3 + HBr → CH3CHBrCH3    (Markovnikov — Br on C2)

Elimination Reactions

Elimination is the reverse of addition. Atoms are removed to form (or extend) a double bond, producing an unsaturated compound. Two main types:

CH3CH2OH ⟶[conc H2SO4, 180°C] CH2=CH2 + H2O    (dehydration)
CH3CHBrCH3 + KOH(ethanol) ⟶[heat] CH3CH=CH2 + KBr + H2O    (dehydrohalogenation)

Substitution Reactions

In substitution, one atom or group is replaced by another without changing the carbon skeleton’s connectivity.

CH3Br + NaOH(aq) → CH3OH + NaBr    (nucleophilic substitution)

Esterification

An ester is formed when a carboxylic acid reacts with an alcohol in the presence of an acid catalyst. The reaction is reversible:

Carboxylic acid + Alcohol ⇌ Ester + Water    (H2SO4 catalyst, reflux)
CH3COOH + CH3CH2OH ⇌ CH3COOCH2CH3 + H2O
(ethanoic acid + ethanol ⇌ ethyl ethanoate + water)

Esters have fruity smells and are used in flavourings, perfumes, and solvents. Naming: the alcohol part names the alkyl group (ethyl), and the acid part becomes -oate (ethanoate).

Hydrolysis of Esters

Hydrolysis is the reverse of esterification — water breaks the ester bond. Two types:

CH3COOCH2CH3 + NaOH(aq) → CH3COONa+ + CH3CH2OH    (saponification)

Cracking

Large alkane molecules from crude oil are broken into smaller, more useful alkenes and alkanes by supplying energy:

C10H22 → C5H12 + C5H10    (one possible cracking product mix)

Combustion

C3H8 + 5O2 → 3CO2 + 4H2O    (complete)
2C3H8 + 7O2 → 6CO + 8H2O    (incomplete)

Polymerisation

Summary Table of Organic Reactions

Reaction typeReactantKey conditionsProduct
Addition (hydrogenation)Alkene + H2Ni catalyst, heatAlkane
Addition (hydration)Alkene + H2OH3PO4, heatAlcohol
Addition (halogenation)Alkene + Br2Room tempDihalogenoalkane
Elimination (dehydration)AlcoholConc H2SO4, heatAlkene + H2O
Substitution (free radical)Alkane + X2UV lightHalogenoalkane + HX
Substitution (nucleophilic)Halogenoalkane + NaOH(aq)HeatAlcohol + NaX
EsterificationCarboxylic acid + AlcoholH2SO4, refluxEster + H2O
Hydrolysis (base)Ester + NaOH(aq)HeatSalt + Alcohol
Combustion (complete)Hydrocarbon + excess O2IgnitionCO2 + H2O
CrackingLong-chain alkaneHigh T or catalystShort alkane + alkene
⭐ IEB Extension — Reaction Mechanisms & Regioselectivity

SN1 vs SN2 (Nucleophilic Substitution):

  • SN2 (bimolecular): One-step; nucleophile attacks as leaving group departs simultaneously. Favoured by primary (1°) halogenoalkanes and strong nucleophiles. Causes inversion of configuration (Walden inversion).
  • SN1 (unimolecular): Two-step; first forms a carbocation intermediate, then nucleophile attacks. Favoured by tertiary (3°) halogenoalkanes in polar protic solvents. Gives racemisation at chiral centres.

E1 vs E2 (Elimination):

  • E2 (bimolecular): Concerted; base removes H while halogen departs simultaneously. Requires anti-periplanar geometry. Favoured by strong bases (KOH in ethanol), primary and secondary substrates.
  • E1 (unimolecular): Two-step via carbocation; favoured by tertiary substrates, weak bases, polar protic solvents.

Regioselectivity: When multiple products are possible (e.g., different alkene positions in elimination), the major product follows Zaitsev’s rule — the more substituted (more stable) alkene is the major product.

Reaction Builder — Select reactant and reaction type to see the balanced equation

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Quiz complete! Review the explanations to strengthen your understanding.
IEB Extension Questions
Answer all questions in your notebook. Write balanced equations with state symbols where required. Always state the conditions (catalyst, temperature, solvent) alongside each equation.
Question 1 — Addition Reactions
Write balanced equations for the following addition reactions. State the conditions required for each:

(a) but-2-ene + H2 → ?
(b) propene + HBr → ? (apply Markovnikov’s rule and name the product)
(c) ethene + Br2(aq) → ? (explain why bromine water is used as a test for unsaturation)
(d) ethene + H2O → ? (name the product)

(8 marks)
Question 2 — Elimination vs Substitution
2-bromopropane can undergo two different reactions with NaOH:

(a) Write the equation for the substitution reaction with NaOH(aq). State the conditions and name the organic product.
(b) Write the equation for the elimination reaction with NaOH in ethanol. State the conditions and name the organic product.
(c) State ONE difference in conditions that determines whether substitution or elimination occurs.

(6 marks)
Question 3 — Esterification
(a) Write the balanced equation for the esterification of propan-1-ol with methanoic acid. Name the ester produced.
(b) The reaction is reversible. State TWO ways to increase the yield of ester at equilibrium.
(c) Explain how saponification (base hydrolysis) differs from acid hydrolysis of an ester.

(6 marks)
Question 4 — Polymerisation
(a) Draw the structural repeating unit of the polymer formed from propene (CH2=CHCH3) by addition polymerisation. Name the polymer.
(b) Explain the difference between addition polymerisation and condensation polymerisation. Include the type of monomer required for each.
(c) Nylon-6,6 is a condensation polymer formed from 1,6-diaminohexane and hexanedioic acid. Write the equation for the first step and identify the small molecule eliminated.

(6 marks)
Question 5 — Reading Esterification Progress Data
Ethanoic acid and ethanol are mixed with a few drops of concentrated H2SO4 catalyst at a constant temperature. The number of moles of ester formed is recorded over time:
Time (min)020406080100
Moles of ester formed (mol)00.200.320.380.400.40
(a) Calculate the average rate of ester formation (in mol·min−1) between t = 0 and t = 20 min, and between t = 80 and t = 100 min.
(b) Explain, in terms of reactant and product concentrations, why the rate calculated in (a) is so much lower in the second interval than in the first.
(c) The amount of ester formed levels off at 0.40 mol after t = 80 min rather than continuing to rise toward the theoretical maximum. Explain why, referring to the nature of the esterification reaction.
(d) Suggest ONE change to the experimental setup (not a change in temperature) that would increase the number of moles of ester present once the system re-settles, and justify it using Le Chatelier’s Principle.

(8 marks)