Grade 8 ยท Mechanical Systems & Control ยท Term 3 ยท Lesson 2

Mechanical Advantage Calculations

Calculate mechanical advantage for levers and gears using simple ratios, represent gear systems graphically, and break a bicycle gear system into a systems diagram.

Revision: lever classes โ€” where's the fulcrum?

Every lever has three key points: the fulcrum (F, the pivot), the load (L, the resistance being overcome) and the effort (E, the force you apply). Which of the three sits in the middle decides the lever's class โ€” and that, in turn, decides what mechanical advantage it can give you.

ClassOrder along the leverExampleMechanical advantage
First-classLoad โ€” Fulcrum โ€” Effort (fulcrum in the middle)See-saw, crowbar, single paper scissorsCan be >1, =1 or <1 depending on arm lengths
Second-classFulcrum โ€” Load โ€” Effort (load in the middle)Wheelbarrow, nutcracker, office punchAlways > 1 โ€” the load arm is always shorter than the effort arm
Third-classFulcrum โ€” Effort โ€” Load (effort in the middle)Tweezers, fishing rod, light-duty staplerAlways < 1 โ€” trades force for extra speed/distance at the load end
Linked lever pairs: most tools you can hold in one hand aren't a single lever โ€” they're two identical levers linked at a shared pivot pin, squeezed together so both act at once. Scissors are two first-class levers pinned at the fulcrum, each half carrying one blade. An office punch or stapler links two second- or third-class levers the same way, so squeezing the handles drives both sides of the jaw or head down together.

Calculating mechanical advantage for levers

Mechanical advantage (MA) compares the load a machine lifts or moves to the effort you put in. For levers, we calculate MA using simple ratios โ€” NOT by "taking moments about a point" (that method comes later, in higher grades). At Grade 8 level, use these two equivalent ratio methods:

MA = Load ÷ Effort   |   MA = Effort arm ÷ Load arm

The effort arm is the distance from the fulcrum to where you apply your effort force. The load arm is the distance from the fulcrum to the load. The longer the effort arm is compared to the load arm, the greater the mechanical advantage.

Worked example: A wheelbarrow lever has an effort arm of 900 mm and a load arm of 300 mm. MA = Effort arm ÷ Load arm = 900 ÷ 300 = 3. This means the wheelbarrow multiplies your effort force three times.
Lever exampleClassMechanical advantage
Paper scissors (equal blade & handle)First-classMA = 1 (no advantage)
Secateurs (long handle, short blade)First-classMA > 1
Office punch / heavy-duty staplerSecond-classMA > 1 (always)
Light-duty stapler / tweezersThird-classMA < 1 (never gives advantage)

Calculating mechanical advantage for gears

For gears, we calculate MA using the ratio of teeth or the ratio of gear wheel diameters, instead of load and effort arms:

MA = Driven gear teeth ÷ Driver gear teeth   =   Driven diameter ÷ Driver diameter

The velocity ratio (VR) works the opposite way around โ€” it tells you how many times the driver must turn to turn the driven gear once:

VR = Driver gear teeth ÷ Driven gear teeth
Worked example: A driver gear has 12 teeth and meshes with a driven gear of 36 teeth. MA = 36 ÷ 12 = 3 (force is tripled). VR = 12 ÷ 36 = 0.33, meaning the driven gear turns at one-third the speed of the driver โ€” three times slower, but three times stronger.

Representing gear systems graphically

Gear systems are drawn using circles (for the pitch circles of each gear) drawn with a pair of compasses or circular templates, sized proportionally to the number of teeth. When sketching gear systems you should be able to show:

Bevel gears: when two bevel gears (cone-shaped gears) are meshed, they transfer the axis of rotation through 90° โ€” useful whenever a machine needs to change the direction a shaft is pointing, such as in a hand drill or a car differential.

Systems diagrams: input → process → output

Any mechanical system can be analysed by breaking it down into three parts: what goes IN, what happens during the PROCESS, and what comes OUT.

Systems diagram for a gear system with MA = 4:1:
INPUT: effort force turning the driver gear (small gear, e.g. 10 teeth) → PROCESS: driver gear meshes with a driven gear four times larger (40 teeth), multiplying the turning force → OUTPUT: output force at the driven gear, four times greater than the input effort, turning four times slower.

System analysis: the bicycle gear system

A bicycle gearing system is a classic real-world gear train, and CAPS uses specific terminology for it:

TermMeaning in a bicycle
Master / driverThe chain wheel (attached to the pedals) โ€” the part you put effort into.
Slave / drivenThe rear cog (attached to the back wheel) โ€” the part that produces the output.
Chain wheelThe large front gear turned directly by the pedal cranks.
Cogs (sprockets)The smaller gears at the back wheel, of different sizes for different gear ratios.

A large chain wheel paired with a small rear cog gives a high velocity ratio โ€” the back wheel spins many times per pedal turn, ideal for speed on flat roads. A small chain wheel paired with a large rear cog gives strong mechanical advantage but a low output speed, ideal for climbing hills.

Mechanical Advantage Calculator

Switch between a lever and a gear system, enter your own values, and see the mechanical advantage calculated live with a matching diagram.

System type
Effort arm (mm)
Load arm (mm)
0/7
Review the explanations above.
Answer in your exercise book. Show all calculation steps.
Question 1 ยท (3 marks)
A lever has an effort arm of 600 mm and a load arm of 150 mm. Calculate the mechanical advantage. Show your formula and working.
Question 2 ยท (3 marks)
A driver gear has 8 teeth and meshes directly with a driven gear of 32 teeth. Calculate (a) the mechanical advantage and (b) the velocity ratio.
Question 3 ยท (4 marks)
Sketch two gear diagrams (circles only, no need to draw teeth): one showing the driven gear rotating in the opposite direction to the driver, and one showing the driven gear rotating in the same direction as the driver. Label which one includes an idler gear.
Question 4 ยท (4 marks)
Draw a systems diagram (input → process → output) for a gear system that gives a mechanical advantage of 4:1.
Question 5 ยท (4 marks)
Using bicycle terminology, name the master (driver) part and the slave (driven) part of a bicycle gear system, and explain why a cyclist shifts to a small chain wheel and large rear cog when climbing a steep hill.
Question 6 ยท (5 marks)
For each of the following, state the lever class (first, second or third) by identifying the order of fulcrum (F), load (L) and effort (E), and state whether the mechanical advantage is always >1, always <1, or can be either: (a) a wheelbarrow, (b) a pair of scissors, (c) a fishing rod. (d) Explain what is meant by a "linked lever pair" and name one example.